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Determinati soluțiile ecuațiilor:
a)(x-2)la a doua-(x+1)la a doua=x-4
b)(2x+3)la a doua+7=4(x-2) la adoua
c)(3x+4)la a doua+20=5(x+1) la a doua+(2x-3)la a doua
Ma puteți ajuta,va rog!


Răspuns :

[tex]a) {(x - 2)}^{2} - {(x + 1)}^{2} = x - 4[/tex]

[tex] {x}^{2} - 4x + 4 - {x}^{2} - 2x - 1 = x - 4[/tex]

[tex] - 4x - 2x - x = - 4 - 4 + 1[/tex]

[tex] - 7x = - 7 \: | \div ( - 7)[/tex]

[tex]x = 1[/tex]

[tex]b) {(2x + 3)}^{2} + 7 = 4 {(x - 2)}^{2} [/tex]

[tex]4 {x}^{2} + 12x + 9 + 7 = 4 {x}^{2} - 16x + 16[/tex]

[tex]12x + 16x = 16 - 9 - 7[/tex]

[tex]28x = 0[/tex]

[tex]x = 0 \div 28[/tex]

[tex]x = 0[/tex]

[tex]c) {(3x + 4)}^{2} + 20 = 5 {(x + 1)}^{2} + {(2x - 3)}^{2} [/tex]

[tex]9 {x}^{2} + 24x + 16 + 20 = 5 {x}^{2} + 10x + 5 + 4 {x}^{2} - 12x + 9[/tex]

[tex]24x - 10x + 12x = 5 + 9 - 16 - 20[/tex]

[tex]26x =- 22[/tex]

[tex]x =- \frac{22}{26} [/tex]

[tex]x = -\frac{11}{13} [/tex]