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Stabiliti daca triunghiurile ABC si MNP sunt asemeneastiind ca: mA=72, mC=2×mB, mN=mP mM=36


Răspuns :

mB+ mC = 180-mA =180-72=108
3mB=108  mB=108:3=36 ⇒mC=72
mN+mP=180-36=144 mN=mP=144:2=72
mA=mN=72 mM=mB=36⇒ΔABC si ΔMNP asemenea