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sa se calculeze:
[tex]( \frac{2}{5} \times 3 \times \frac{1}{3} - 1) \times 1 \times \frac{4}{5} + \frac{1}{10} = [/tex]va rogg



Răspuns :

(2/3*3*1/3-1)*1*4/5+1/10 =

= (2*1/3-1)*4/5+1/10 =

= (2/3 -1)*4/5+1/10 =

= (-1/3)*4/5+1/10 =

= -4/15 +1/10 = -1/6