Notam cu x,y si z segmentele
[tex](x,y,z)\ direct\ proportionale\ cu\ (1,2,3)\\\\\frac{x}{1}=\frac{y}{2}=\frac{z}{3}=k(variabila\ oarecare)\\\\x=k\\\\y=2k\\\\z=3k\\\\k+2k+3k=9,6\ cm\\\\6k=9,6\\\\k=9,6:6=1,6\\\\x=k=1,6cm\\\\y=2k=3,2cm\\\\z=3k=4,8cm[/tex]
