Se da :
F1=500N
F2=900N
∆l1=2cm
Se cere:
∆l2=?
K-constanta elastica
K=F1:∆l1
K=500N:2cm
K=250N/cm
∆l2=F2:K
∆l2=900N:250N/cm
∆l2=3.6 cm
F = kΔl
stim deformarea Δl = 2 cm = 0,02 m si Forta F = 500 N
putem afla constanta resortului k = F : Δl = 500 N : 0,02 m = 25 000 N/m
la F1 = 900 N, deformarea Δl = F : k = 900 N : 25000 N/m = 0,036 m = 3,6 cm
