425 g xg
CaCO3 =CaO + CO2
100g 56g
MCaCO3=40+12+3.16=100------->1mol=100g
MCaO=40+16=56---->1mol=56g ; Se calc puritatea CaCO3:
x=425.56:100=238g CaO ; mp=p.mt:100=85.500:100=
CaO react. cu apa si formeaza Ca(0H)2 425g
238g yg
CaO + H2O= Ca(OH)2
56g 74g
MCa(OH)2=40+2.16+2=74------->1mol=74g
y=238.74 :56=3145 g Ca(OH)2