Exercitiul 3 va rog. Multumesc anticipat

[tex]\displaystyle\bf\\\sqrt[\b3]{\bf x+2}+2=0\\\\\sqrt[\b3]{\bf x+2}=-2~~\Big|~(~)^3}\\\\\Big(\sqrt[\b3]{\bf x+2}\Big)^3=\Big(-2\Big)^3\\\\x+2=-8\\\\x=-8-2\\\\\boxed{\bf x=-10}[/tex]