👤

determinati numarul natural care are patratul egal cu 2 la puterea 16+2 la puterea 9+1

Răspuns :


[tex]\it n^2=2^{16} + 2^9+1 =(2^{8})^2+2\cdot2^8+1 =(2^8+1)^2 \Rightarrow \\ \\ \Rightarrow n = 2^8+1=256+1=257[/tex]