Determinați numerele x,y si z stiind ca x/2=y/3=z/7 si x × y × z = 336

x/2=y/3=z/7 = k => x=2k ; y = 3k si z = 7k
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inlocuim in
x × y × z = 336
⇒ 2k×3k×7k = 336 |:6
7×k³ = 56 |:7
k³ = 8 = 2³ deci k = 2
⇒ x = 2*2 = 4 ; y = 3*2 = 6 si z = 7*2 = 14