abc+dbc+ebc=1916
100a+10b+c+100d+10b+c+100e+10b+c=1916
100(a+d+e)+30b+3c=1916
100(a+d+e)+3(10b+c)=1916
100(a+d+e)+3bc=1916
100(a+d+e)+3bc=1700+ 216; (pentru ca 216 este divizibil cu 3)
100(a+d+e)+3•bc=100•17 + 3•72
=> a+d+e=17 si bc=72, deci, b=7 si c=2
a+d+e+b+c=17+7+2= 26
