ms = p (ro) x Vs = 700 x 0,79 = 553 g alcool etilic (etanol)
553 g..................................................... n moli
CH3-CH2-OH __H2SO4/toC__> CH2=CH2 + H2O
46 g/mol ................................................ 1
=> n = 553 / 46 = 12,022 moli C2H4
randamentul (eta) = Cpx100/Ct => Cp = Ct x (eta) / 100 = 12,022x80/100
=> Cp = 9,62 moli C2H4 s-au obtinut in final
PV = nRT => V = nRT/P = CpRT/P
=> V = 9,62x0,082x(273+27) / 2 = 118,3 L etena