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[tex]1.1(3) + 0.(6) + 1.25[/tex]


Răspuns :

[tex]1,1(3) = \frac{113-11}{90} =  \frac{102}{90} =  \frac{17}{15}[/tex]

[tex]0,(6) = \frac{6}{9} =  \frac{2}{3}[/tex]

[tex]1,25 = \frac{125}{100} = \frac{5}{4}[/tex]

=>

[tex]\frac{17}{15}+ \frac{2}{3} + \frac{5}{4} =  \frac{17*4+2*20+5*15}{60} = \frac{68+40+75}{60} = \frac{183}{60} =  \frac{61}{20}[/tex]

102/90 + 6/9 + 125/100 =        ...aducem la acelasi numitor ...900

1020/900 + 600/900 + 1125/900 = 2745/900⁽⁵ = 545/180⁽⁵ = 109/36