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Descompuneti pe: 125,225,25 ca o putere avand baza 5.
Baza 3: 9,27,36,81
Baza 2: 4,16,32
Va roog,ajutati-ma imi trebuie pentru maine!Dau coroana.


Răspuns :

125=[tex]5^{3}[/tex]

225=[tex]5^{2}[/tex]·[tex]3^{2}[/tex]

25=[tex]5^{2}[/tex]

9=[tex]3^{2}[/tex]

27=[tex]3^{3}[/tex]

36=[tex]3^{2}[/tex]·4

81=[tex]3^{4}[/tex]

4=[tex]2^{2}[/tex]

16=[tex]2^{4}[/tex]

32=[tex]2^{5}[/tex]

SUCCES!!!

125 = 5 × 25 = 5 x 5² = 5³

225 = 5 × 45 = 5² × 3²=  15² → sigur era 625 = 5 × 125 = 5⁴

25 = 5²

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9 = 3 x 3 = 3²

27 = 3³

36 = 2² x 3² =  (2 x 3 ) ² = 6²

81 = 9 x 9  = 3² x 3² = 3 ⁽ ² ⁺ ² ⁾ = 3⁴

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4 = 2²

16 = 4² = 2⁴

32 = 16 x 2 = 2⁴ x 2 = 2⁵