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2) Rezolvati : A) (2+radical din 3) la 2

Răspuns :

(2+rad3)^2=2^2+2×2× rad 3 + rad 3^2= 4+4 rad 3 + 3 = 7 + 4 radical din 3. Greseala mea.....
[tex] {(2 + \sqrt{3} )}^{2} = {2}^{2} + 2 \times 2 \times \sqrt{3} + {( \sqrt{3} )}^{2} [/tex]

[tex] = 4 + 4 \sqrt{3} + 3[/tex]

[tex] = 7 + 4 \sqrt{3} [/tex]

[tex]Formul\check{a}\:: \: {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} [/tex]