CuO
raport atomic=r.a.
r.a.=1Cu : 1 O=1: 1
raport de masa =r.m.
r.m.=ACu : AO=64 :16 [se simplifica cu 16 ]
=4: 1
Comp. proc. prin masa moleculara
MCuO=64 +16=80----->1mol=80g
80g CuO--------64 gCu--------16g O
100g Cu-----------x g Cu--------yg O
X=1oo.64 :80=80 la suta Cu
y=100.16 :80=20 la suta O
H2SO4
r.a.=2H :1S :4O=2 : 1 : 4
r.m.=2AH : AS : 4AO=2 :32: 4.16
=2 :32 : 64 [se simplif.cu 2 ]
=1:16 :32
Comp.proc.prin masa moleculara
MH2SO4=2+32+4.16=98-----> 1mol=98 gH2SO4
98g H2SO4--------2g-------32g S--------64g O
100 g H2SO4------xg--------yg----------------zg
x=100.2 :98=2,04 la suta H
y=100.32 :98=32,65 la suta S
Z=100.64 :98=65,30 la suta O
Al(OH)3
Dupa modele incearca sa lucrezi singur .
