ma puteti ajuta la ex. 1 punctul i)

[tex]8^{16}:(2\cdot2^{4}\cdot 2^{10})^{3}-2^{1}-2^{0}=\\ \\ 2^{3\cdot16}:(2^{1+4+10})^{3}-2-1=\\ \\2^{48}: 2^{15\cdot3}-3= \\ \\ 2^{48}:2^{45}-3=\\ \\2^{48-45}-3=\\ \\2^{3}-3=8-3=5[/tex]