Avem o inmultire de doua paranteze din care se va scadea o paranteza ridicata la puterea 2 = 3
(x+4)(x+2)=x^2+4x+2x+8=x^2+6x+8
(x+1)^2
Deci (x+1)^2=(x+1)(x+1)=x^2+2x+1
Pana acum avem: | x^2+6x+8-x^2-2x-1 |=3
Adica: |4x+7|=3
|4x|+|7|=3
4x+7=3
4x=3-7
4x=-4
x=-1
Proba:
|(-1+4)(-1+2)-[(-1)(-1)+2(-1)+1|=|3*1-[(1-2+1)|=|3|-0=3-0=3