b: _______/
a : _______/________/
c: _____...51
d: _______/________/__ 51 .... total 666
la a 4-a am pus 51....pentru ca era lipsa la ultimul segment 51...si am completat din 102 si ne-a ramas 51
daca observam ...la c lipseste 51 ....iar d are in plus 51....deci avem 6 segmente egale
666: 6=111 (un segment)
deci :
b= 111 alune
a= b*2
a = 111*2
a=222 (alune)
c= b-51
c= 111-51
c=60(alune)
d= b+c+102
d= 111+60+102
d= 273(alune)
