71 g xg
H2 + Cl 2=2 HCl
71g 2.36,5g
3
1litru=1dm ( dm cub )
22,4 dm cub=22,4 litri Cl2
Se calc. molii de Clor
n =m:M----> n=22,4 : 22,4=1 mol
1mol de clor =2.35,5g=71 g Cl2
Se calc. x
x=71 .2.36,5: 71=73 g HCl MHCl=1+35,5=36,5---->1mol=36,5 g
n=m:M
n=73:36,5= 2moli HCl