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se considera nr a=log5din2 .Arătați ca log5din10=1+a
helppp


Răspuns :

[tex]a = log_{5}(2) [/tex]

[tex] log_{5}(10) = 1 + a[/tex]

[tex]1 = log_{5}(5) [/tex]

[tex] log_{5}(10) = log_{5}(5) + log_{5}(2) [/tex]

[tex] log_{5}(10) = log_{5}(5 \times 2) [/tex]

[tex] log_{5}(10) = log_{5}(10) \: \: (A)[/tex]

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