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calculați 1supra 4 + 1 supra 4 :(1 supra 4 +1 supra 4 ×1 supra 2) × 3 supra 4


DAU COROANAAA


Răspuns :

[tex] \frac{1}{4} + \frac{1}{4} : ( \frac{1}{4} + \frac{1}{4} \times \frac{1}{2}) \times \frac{3}{4} = \frac{1}{4} + \frac{1}{4} : ( \frac{1}{4} + \frac{1 \times 1}{4 \times 2}) \times \frac{3}{4} = \frac{1}{4} + \frac{1}{4} : ( \frac{1}{4} + \frac{1}{8}) \times \frac{3}{4} = \frac{1}{4} + \frac{1}{4} : \frac{3}{8} \times \frac{3}{4} = \frac{1}{4} + \frac{1}{4} \times \frac{8}{3} \times \frac{3}{4} = \frac{1}{4} + \frac{1 \times 8 \times 3}{4 \times 3 \times 4} = \frac{1}{4} + \frac{24}{48} = \frac{1}{4} + \frac{1}{2} = \frac{3}{4} [/tex]