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rationalizata fractia: radical din 2+ radical din 5/2radical din5 este:

Răspuns :


[tex] \sqrt{2} + \frac{ \sqrt{5} }{2 \sqrt{5} } = \sqrt{2} + \frac{( \sqrt{5}) {}^{2} }{2 \times ( \sqrt{5}) {}^{2} } = \sqrt{2} + \frac{5}{2 \times 5} = \sqrt{2} + \frac{5}{10} = \sqrt{2} + \frac{1}{2} = \frac{2 \sqrt{2} + 1 }{2} [/tex]

[tex] \sqrt{2} + \frac{ \sqrt{5} }{2 \sqrt{5} } = \sqrt{2} + \frac{ \sqrt{5} \sqrt{5} }{2 \times 5} = \sqrt{2} + \frac{ \sqrt{25} }{2 \times 5} = \sqrt{2} + \frac{5}{2 \times 5} = \sqrt{2} + \frac{5}{10} = \sqrt{2} + \frac{1}{2} [/tex]