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Rezolvati ecuatia 2x-1 supra - x supra 3= x+ 3 supra 6 ∈ R

Răspuns :

[tex] \frac{2x-1}{\frac{-x}{3}}=\frac{x+3}{6} [/tex]

[tex] \left(2x-1\right)\cdot \:6=\frac{-x}{3}\left(x+3\right [/tex]

[tex] \frac{2x-1}{\frac{-x}{3}}=\frac{x+3}{6} \\ \\ (2x-1)\cdot6\cdot3=-\frac{x}{3}\cdot(x+3)\cdot3\\ \\ 18\cdot(2x-1)=-x(x+3)\\ \\ 36x-18=x^{2} -3x\\ \\ -x^{2} -3x=36x-18\\ \\ -x^{2} -39x+18=0\\ \\ [/tex]

x₁=(-39+3√177)/2

x₂=(-39-3√177)/2