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Calculati
(√5+2) totu la a doua+|5-3|-√45


Răspuns :

(√5+2)²+|5-3|-√45=

=5+2*√5*2+4+|2|-3√5=

=5+4+2+4√5-3√5=

=11+√5


[tex] {( \sqrt{5} + 2) }^{2} + |5 - 3| - \sqrt{45} = \\ \\ ( \sqrt{5} + 2) ^{2} + |2| - \sqrt{45} = \\ \\ {( \sqrt{5} + 2) }^{2} + 2 - 3 \sqrt{5} = \\ \\ \sqrt{5} ^{2} + 2 \sqrt{5} \times 2 + {2}^{2} + 2 - 3 \sqrt{5} = \\ \\ 5 + 2 \sqrt{5} \times 2 + 4 + 2 - 3 \sqrt{5} = \\ \\ 5 + 4 \sqrt{5} + 4 + 2 - 3 \sqrt{5} = \\ \\ (5 + 4 + 2) + (4 \sqrt{5} - 3 \sqrt{5}) = 11 + \sqrt{5} [/tex]