alcanul CnH2n+2, are masa molara ,M= 14n+2, g/mol
ecuatia reactiei de diclorurare : CnH2n+2 +2Cl2---> CnH2nCl2+ 2HCl,
masa molara a derivatului diclorurat ,M= 14n+2x35,5, g/mol
in 14n+71g derivat...se gasesc ....12n,gC
100g............................................................24,24g
1200n= 339,4n+1721----> n= 2-----> alcanul este etena
1mol...........2mol.........1mol
C2H6 + 2Cl2----> C2H4Cl2 +2HCl
x.............y,,,,,,,,,,,,,,,,,,,0,2mol, deoarece n(niu)= 19,8g/99g/mol
x= 0,2mol etena si y= 0,4mol Cl2
V,etena= 0,2molx22,4l/mol=.................calculeaza !!!!
V,Cl2= 0,4molX22,4 l/mol=.......................calculeaza !!!!
