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integrala de la 1 la 2 (4x+2)dx

Răspuns :

Salut,

[tex]\int_1^2(4x+2)dx=\left(4\cdot\dfrac{x^2}2+2x\right)\Bigg{|}_1^2=\left(4\cdot\dfrac{2^2}2+2\cdot 2\right)-\left(4\cdot\dfrac{1^2}2+2\cdot 1\right)=\\\\=12-4=8.[/tex]

Green eyes.