Solutia ecuatiei????????????????????

x²-3x+m=0 => x₁ = [3+√(9-4m)]/2
x₂ = [3-√(9-4m)]/2
x₁² -x₂² = [9+9-4m+6√(9-4m)]/4 - [9+9-4m-6√(9-4m)]/4 = 3√(9-4m) =27 =>
√(9-4m) = 9 I² => I9-4mI=81 => 4m = - 72 => m = - 18
=> 4m = 90 => m = 45/2