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2x+y 2
------- = ----
3x-y 3

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Răspuns :


[tex] \frac{2x + y}{3x - y} = \frac{2}{3} \\ \\ \frac{2x + y}{3x - y} \times \frac{3}{3} = \frac{2}{3} \times \frac{3x - y}{3x - y} \\ \\ \frac{2x \times 3 + y \times 3}{3(3x - y)} = \frac{2}{3} \times \frac{3x - y}{3x - y} \\ \\ \frac{6x + 3 \times y}{3(x - y)} = \frac{2}{3} \times \frac{3x - y}{3x - y} \\ \\ \frac{6x + 3y}{3(3x - y)} = \frac{2}{3} \times \frac{3x - y}{3x - y} \\ \\ \frac{6x + 3y}{3(3x - y)} = \frac{2(3x) + 2( - y)}{3(3x - y)} \\ \\ \frac{6x + 3y}{3(3x - y)} = \frac{6x + 2( - y)}{3(3x - y)} \\ \\ \frac{6x + 3y}{3(3x - y)} = \frac{6x - 2y}{3(3x - y)} \\ \\ 6x + 3y = 6x - 2y \\ \\ 6x + 3y + 2y = 6x \\ \\ 6x + 5y = 6x \\ \\ 5y = - 6x + 6x \\ \\ 5y = 0 \\ \\ \frac{5y}{5} = \frac{0}{5} \\ \\ y = \frac{0}{5} \\ \\ y = 0 [/tex]

( 2 x + y ) / ( 3 x - y ) = 2 / 3


⇒ 3 ( 2 x + y ) = 2 ( 3 x - y ) → produsul mezilor = produsul extremilor


6 x + 3 y = 6 x - 2 y


3 y + 2 y = 6 x - 6 x


5 y = 0 ⇒ y = 0