Aplici regula ridicarii la putere si obtii:
[tex] f'(x)=\frac{\mathrm{d}}{\mathrm{d}x}(x+2)^3=3(x+2)^2\cdot\frac{\mathrm{d}}{\mathrm{d}x}(x+2)[/tex]
Cum parametrul [tex]x[/tex] are derivata 1 si constanta [tex]2[/tex] are derivata [tex]0[/tex]:
[tex]f'(x)=3(x+2)^2=3(x^2+4x+4)=3x^2+12x+12\:\forall\: x\in \mathbb{R} [/tex]
