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In reperul cartezian xOy se considera punctele A(-3,1) si B (7,1)
Determinati coordonatele mijocului segmentului AB


Răspuns :

[tex] M_{AB} = [ \frac{x1+x2}{2} ; \frac{y1+y2}{2}] => \frac{-3+7}{2} ; \frac{1+1}{2} => M_{AB} = (2 ; 1) [/tex]

[tex] A(-3;1) \\ \\ B(7;1) \\ \\ \\
\mathbb{NOTATIE} \rightarrow \text{Fie M mij [AB]} \\ \\

X_M = \dfrac {X_A+X_B}{2} \\ \\
X_M = \dfrac {-3+7}{2} \\ \\
X_M = \dfrac {4}{2} \\ \\
X_M = 2 \\ \\ \\ \\


Y_M = \dfrac {Y_A+Y_B}{2} \\ \\
Y_M = \dfrac {1+1}{2} \\ \\
Y_M = \dfrac {2}{2} \\ \\
Y_M = 1 \\ \\ \\ \Rightarrow \boxed{\boxed { M(2;1)}} [/tex]