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Rezolvați in Q


6(1-x)=6x+6
X supra 2 + x supra 3 + x supra 4=X-1 supra 12



Răspuns :

6(1-x)=6x+6

6-6x=6x+6

-6x-6x=6-6

-12x=0

x=0.


x/2+x/3+x/4=(x-1)/12

x/2+x/3+x/4-(x-1)/12=0

6x+4x+3x-x+1=0

12x+1=0

12x=-1

x=-1/12.

Bafta!


6 ( 1 - x ) = 6 x + 6

6 ( 1 - x ) = 6 ( x + 1 ) l ( : 6 )

1 - x = x + 1

- x - x = 1 - 1

- 2 x = 0

x = 0



x / 2 + x / 3 + x / 4 = ( x - 1) / 12 → le aduc la acelasi numitor 12


6 x + 4 x + 3 x = x - 1

13 x - x = - 1

12 x = - 1

x = - 1 / 12


Daca x nu este supra 12, atunci avem:


x / 2 + x / 3 + x / 4 = x - 1 / 12

6 x + 4 x + 3 x = 12 x - 1

13 x - 12 x = - 1

x = - 1