[tex] \dfrac{\sqrt 3}{2} ~\square~ \dfrac{1}{\sqrt 2}\Big|^2\\ \\ \Big(\dfrac{\sqrt 3}{2}\Big)^2~\square ~\Big(\dfrac{1}{\sqrt 2} \Big)^2 \\ \\ \dfrac{3}{4}~ \square ~\dfrac{1}{2} \\ \\\dfrac{4-1}{4} ~\square ~\dfrac{2-1}{2} \\ \\1- \dfrac{1}{4}~\square~ 1- \dfrac{1}{2} \\ \\ - \dfrac{1}{4} > - \dfrac{1}{2} \\ \\ \Rightarrow \dfrac{\sqrt 3}{2} > \dfrac{1}{\sqrt 2} [/tex]
