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cum se scad doua puteri cu acelasi exponent,dar cu baze diferite?

Răspuns :

[tex]\\ (5^{12}:5^{10}-4^{18}:4^{16}):3^2 \\ Formula: \boxed{ \frac{x^a}{x^b}\:=\:x^{a-b}} \\ 5^{12}:\:5^{10} = \frac{5^{12}}{5^{10}}= 5^{12-10}= 5^2 = 25 \\ 4^{18}:4^{16} = \frac{4^{18}}{4^{16}}=4^{18-16}= 4^2 = 16 \\ 3^2 = 9 \\ Acum \:\ vine: (25-16) : 9 =\ \textgreater \ (9):9 =\ \textgreater \ 9:9 = 1[/tex]