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[tex] \frac{1}{ \sqrt{3 } + \sqrt{2} } [/tex]


Răspuns :

[tex]\frac{1}{\sqrt{3}+\sqrt{2}} = \frac{1\cdot \left(\sqrt{3}-\sqrt{2}\right)}{\left(\sqrt{3}+\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)} = \frac{\sqrt{3}-\sqrt{2}}{1} = \sqrt{3}-\sqrt{2}[/tex]