R–COCl + R'–OH–––>R–COOR' + HCl
A=R–COCl
B=R'–OH
C=R–COOR'
mA=27g
mC=29,66g
η=98%
MA+MC=166,5
A=?, B=?, C=?
η–se referă la substanța C
mC–masa practică=mp
mt–masa teoretică
η=mp*100/mt=>mt=mp*100/η=29,66*100/98=30,26g C
ν1=mA/MA=27/MA
ν2=mB/MB=30,26/(166,5–M1)
1 mol R–COCl...............1 mol R–COOR'
27/MA.........................30,26/(166,5–MA)
27/MA=30,26(166,5–MA)
30,26MA=27(166,5–MA)
30,26MA=4495,5–27MA
(30,26+27)MA=4495,5
57,26MA=4495,5
MA=78,5g/mol R–COCl
MC=166,5–78,5=88g/mol R–COOR'
R–COCl:
MA=12n+2n+1+12+16+35,5=(14n+64,5)g/mol
MA=78,5g/mol
=>14n+64,5=78,5=>14n=14=>n=1
R=CH3
Deci A=CH3–COCl
R–COOR'=CH3–COOR'
MC=12+3+12+32+12n+2n+1=(14n+60)g/mol
MC=88g/mol
=>14n+60=88=>14n=28=>n=2
R'=CH2–CH3
Deci C=CH3–COO–CH2–CH3
=>R'–OH=CH3–CH2–OH=B
Reacție:
CH3–COCl + CH3–CH2–OH–––> CH3–COO–CH2–CH3 + HCl
Răspuns corect:
B. Clorură de acetil, etanol, acetat de etil.
