[tex] \lim_{x \to \ 3} (\frac{x+4}{x-2}) = \frac{3+4}{3-2}= \frac{7}{1} = \boxed{7}[/tex]
[tex]\\Sau \:\ daca \:\ ai \:\ 4 \:\ pe \:\ x \:\ doar \:\ vine \:\ in \:\ felul \:\ urmator:
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\\\lim_{x \to \ 3} (x+\frac{4}{x}-2) = 3+\frac{4}{3}-2 = \frac{9+4-6}{3} = \boxed{\frac{7}{3}}[/tex]
