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Rezolvarea este anexata !
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Vezi imaginea ALITTA
   
[tex]\displaystyle\\ a)\\ \sqrt{15} \ \textless \ \sqrt{16} = 4\\ \sqrt{225} = 15\\ \Longrightarrow~~ x \in \{4;~5;~6;~7;~8;~9;~10;~11;~12;~13;~14;~15\}\\ \Longrightarrow~~A=\{4;~5;~6;~7;~8;~9;~10;~11;~12;~13;~14;~15\}\\\\ b)\\ \text{Nr de elemente ale multimii } = 15 - 4 + 1 =11+1 = 12 \text{ elemente.}\\ \text{Cazuri favorabile: }~\{4;~9\}~~~2 \text{ elemente}\\ p = \frac{2}{12}= \frac{1}{6}[/tex]