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Ma ajuta careva la expresie?Va rog.Vreau sa stiu daca am facut la examen bine.Multumesc din suflet.

Ma Ajuta Careva La ExpresieVa RogVreau Sa Stiu Daca Am Facut La Examen BineMultumesc Din Suflet class=

Răspuns :

[tex]E(x)=( \frac{x+1}{x-3}- \frac{2x^{2} +3x-3}{ x^{2} -9}+ \frac{2x-1}{x+3}):( \frac{2x^{2}-18}{ x^{2} +6x+9} \\ \\ \frac{(x+1)(x+3)-(2 x^{2} +3x-3)+(2x-1)(x-3)}{ x^{2} -9} :( \frac{2(x^{2}-9)}{ x^{2} +3x+3x+9}) \\ \\ \frac{ x^{2} +3x+x+3-2 x^{2} -3x+3+(2 x^{2} -6x-x+3)}{(x-3)(x+3)} :\frac{2(x^{2}-9)}{ (x+3) ^{2}} \\ \\ \frac{ x^{2}-6x+9}{(x-3)(x+3)} \cdot \frac{(x+3)(x+3)}{2(x+3)(x-3)} = \\ \\ \frac{ (x-3)^{2} }{(x-3)} \cdot \frac{1}{2(x-3)} = \\ \\E(x)= \frac{1}{2} [/tex]