Aria unui romb = [tex] \frac{d1*d2}{2} [/tex]
Consider rombul ABCD
AB= 85m
AC= 168m
AC n BD = {O}
AO=OC= d/2 = 168/2 = 84m
AC _|_ BD ⇒ ΔAOB= dreptunghic, m(O)=90° ⇒ Aplic Teorema lui Pitagora
AO²+OB²=AB²
7056 + OB² = 7225
OB² = 169
OB= √169
OB= 13
BD= 2OB = 2*13= 26cm
d1*d2 = 26*168= 4368
A= (d1*d2)/2 = 4368/2 = 2184 cm²
