a)A,C,B coliniare==>
|xa ya 1| |-1 3 1|
|xb yb 1| =0==> |0 a+1 1| =0 ==>-(a+1)+0+6-2(a+1)+2a-0=0
|xc yc 1| |2 2a 1|
-a-1+6-2a-2+2a=0
-a+3=0==>a=3
b) |2 a-2 1|
|a 2a 1| =0 ==>> 4a+a-2-a-2a-a^2+2a+2=0
|1 -1 1|
4a-a^2=0
a(4-a)=0
a=0 sau a=4
SAUU
A,B,C coliniare==>AB+BC=AC