1. MgO , CaO
2. 2NaOH + H2SO4 = Na2SO4 + 2H2O
3KOH + FeCl3 = Fe(OH)3 + 3KCl
Cu(OH)2 => CuO + H2O
Cu + H2O - imposibila ( merge doar CuO + H2O)
2Al(OH)3 + 3H2SO4 = Al2(SO4)3 + 6H2O
3.
M NaOH = 23 + 16 + 1 = 40 g
M H2SO4 = 2 + 32 + 64 = 98g
v = nr de moli = Masa subst / masa molara
nr de moli de H2SO4 = 128/98 = 1.30 moli
x 1.30 moli
2NaOH + H2SO4 = Na2SO4 + 2H2O
2moli 1mol 1mol 2moli
=> x = 1.30 * 2 = 2.60 moli NaOH = 2.60 * 40 g = 104 g
Sper ca te-am ajutat !