[tex]1,(5):\frac23-\{{16\frac25-\big[14+(\frac38+\frac58*2\frac35)\big]\}}= \\ \\ 1\frac59*\frac32-\{\frac{16*5+2}{5}-\big[14+(\frac38+\frac58*\frac{2*5+3}{5})\big]\}}= \\ \\ \frac{1*9+5}{9}*\frac32-\{{\frac{82}{5}-\big[14+(\frac38+\frac58*\frac{13}{5})\big]\}}= \\ \\ \frac{14}{9}*\frac32-\{{\frac{82}{5}-\big[14+(\frac38+\frac{13}{8})\big]\}} = \\ \\ \frac{7}{3}-\big[\frac{82}{5}-(14+\frac{16}{8})\big]= \\ \\ \frac73-(\frac{82}{5}-16)= \\ \\ \frac73-(\frac{82}{5}-\frac{80}{5})= \\ \\ \frac73-\frac25=[/tex]
[tex]\frac{35}{15}-\frac{6}{15}= \frac{29}{15}[/tex]
