MAl2(SO4)3 =2.27+3.32+12.16=342------->1mol=342 g
Daca in 342g se afla 2.27=54 g Al atunci in 2,16 g se afla Xg sulfat de Al
342 gAl2(SO4)3-----------54 g Al
xg-----------------------------2,16 g
x=342.2,16:54=13,68 g Al2(SO4)3