h=vo•t1+g•t1^2/2=5t1^2
h=c•t2
5t1^2=c•t2
t=t1+t2=>t2=t-t1=0,2-t1
5t1^2=340(0,2-t1)<=>5t1^2=68-340t1
5t1^2+340t1-68=0
Δ=340^2+5•4•68=115600+1360=116,960
t1'=(-340+√116,960)/10=1,99/10=0,199 s
t1=t1'=0,199 s
h=5t1^2=5•0,199^2=0,19 m
Mai verifica tu o data calculele nu mi se pare inregula
