x=0.166 moli 0.05 moli
10Fe + 6KNO₃ ---------> 5Fe₂O₃ + 3N₂ + 3K₂O
10 moli 3 moli
[tex] V_{N_2}=1,12\ L \\ n_{N_2}=\frac{1,12}{22,4}=0,05\ moli \\ n_{Fe}=x=0,166\ moli \\ m_{Fe}=0,166*56=9,33\ g [/tex]
[tex] n_{KNO_3}=y=0,1\ moli \\ m_{KNO_3}=0,1*101=10,1\ g\ (m_d) \\ \\ m_s=\frac{m_d*100}{C}=\frac{10,1*100}{25}=40,4\ g\ KNO_3 [/tex]