Mcristalohidrat = 160+90 = 250g/mol
250g crist.........160g CuSO4......90g H2O
25g crist.............16g CuSO4.........9g H2O
% C = md/ms×100 = 16/25×100 = 64
a) m H2O = 6,01 ×18 = 108,18g
msf = 25+108,18 = 133,18g
C = md/msf×100 = 16/133,18×100 = 12%
b) msf = 36+25 = 61g
C = md/msf×100 = 16/61×100 = 26,22%
Celelalte doua variante se exclud deorece daca se adauga sare o sa creasca concentratia initiala de 64%.
R: a)
