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Daca f:R->R ,f(x) =ax-3,a apartine R , calculati a=? daca f(-5)=2

Răspuns :

f(x) =ax-3
f(-5)=2
- 5a - 3 = 2
- 5a = 2 + 3
- 5a = 5
a = 5/ - 5
a = - 1
f:R->R,   f(x) = - x - 3