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Derivata f(x) =x+1/x-1

Răspuns :


[tex]f'(x)=\left(\dfrac{x+1}{x-1}\right)^{'}=\dfrac{(x+1)'\cdot (x-1)-(x-1)'\cdot (x+1)}{(x-1)^2} = \\ =\dfrac{x-1-x-1}{(x-1)^2}=\boxed{-\dfrac{2}{(x-1)^2}} [/tex]