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Rezolvati ecuatiile
x la a 2 = 1
x la 2 = 81
4x la 2 = 1
2x la 2 = 8
3x la 2 = 75
49 x la 2= 121
25 x la 2 = 225
36 x la 2 = 144
Va rog ajutati-ma macar umpic
Urgent!!!!!!!!!!!!!!!!!!!
Dau coroana


Răspuns :

Eu o sa le numerotez ca sa nu le incurci intre ele :)

1)
[tex] {x}^{2} = 1 \\ x = \sqrt{1} \\ x = |1| \\ x = 1 \: sau - 1[/tex]
2)
[tex] {x}^{2} = 81 \\ x = \sqrt{81} \\ x = |9| \\ x = 9 \: sau \: -9[/tex]
3)
[tex] {4x}^{2} = 1 \\ {x}^{2} = \frac{1}{4} \\ x = \sqrt{ \frac{1}{4} } \\ x = | \frac{1}{2} | \\ x = \frac{1}{2} \: sau \: - \frac{1}{2} [/tex]

4)
[tex] {2x}^{2} = 8 \\ {x}^{2} = \frac{8}{2} \\ {x}^{2} = 4 \\ x = \sqrt{4} \\ x = |2| \\ x = 2 \: sau \: - 2[/tex]
5)
[tex] {3x}^{2} = 75 \\ {x}^{2} = 25 \\x = \sqrt{25} \\ x = |5| \\ x = 5 \: sau \: - 5[/tex]
6)
[tex] {49x}^{2} = 121 \\ {x}^{2} = \frac{121}{49} \\ x = \sqrt{ \frac{121}{49} } \\ x = | \frac{11}{7} | \\ x = \frac{11}{7} \: sau \: - \frac{11}{7} [/tex]
7)
[tex] {25x}^{2} = 225 \\ {x}^{2} = \frac{225}{25} \\ x = \sqrt{ \frac{225}{25} } \\ x = | \frac{15}{5} | \\ x = 3 \: sau \: - 3[/tex]
8)
[tex] {36x}^{2} = 144 \\ {x}^{2} = \frac{144}{36} \\ x = \sqrt{ \frac{144}{36} } \\ x = | \frac{12}{6} | \\ x = 2 \: sau \: - 2 [/tex]