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Determinati concentratia molara finala a solutiilor obtinute prin amestecarea a doua solutii de HCl cu Cm1=3M si Cm2=5M,in raport volumeric 1:2

Răspuns :

c3= n3/V3= (n1+n2)/(V1+V2)
V1/V2= 1/2---> V2=2V1---> V1+V2= 3V1

n1= c1xV1= 3V1
n2= c2xV2= 5V2=10V1---n1+n2= 13V1

c3= 13V1/3V1= 13/3= 4,3M